x^2-16x+220=0

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Solution for x^2-16x+220=0 equation:


Simplifying
x2 + -16x + 220 = 0

Reorder the terms:
220 + -16x + x2 = 0

Solving
220 + -16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-220' to each side of the equation.
220 + -16x + -220 + x2 = 0 + -220

Reorder the terms:
220 + -220 + -16x + x2 = 0 + -220

Combine like terms: 220 + -220 = 0
0 + -16x + x2 = 0 + -220
-16x + x2 = 0 + -220

Combine like terms: 0 + -220 = -220
-16x + x2 = -220

The x term is -16x.  Take half its coefficient (-8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
-16x + 64 + x2 = -220 + 64

Reorder the terms:
64 + -16x + x2 = -220 + 64

Combine like terms: -220 + 64 = -156
64 + -16x + x2 = -156

Factor a perfect square on the left side:
(x + -8)(x + -8) = -156

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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